
7Applications
7.10 Chain conveyor
134
Lenze · Drive Solution Designer · Manual · DMS 4.2 EN · 12/2013 · TD23
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Required torque of the application (with losses)
Provided that the friction torque of the application is proportional to the torque to be transmitted,
the torque of the application can be calculated with the following equation:
[7-117] Equation 11: Required torque of the application (with losses)
Tip!
Further equations to complete the calculations required for an application can be found in
the chapter "Basic calculations
". ( 68)
7.10.1.1 Symbols used
M
th,App
M
App
M
App
ω
ω
------ -
1
η
Chn
------------
1–
⋅⋅+=
Symbol Description Dimension unit
a Acceleration (translatory) m/s
2
d Diameter of the drive roll mm
F
μ
Friction force N
F
g
Lifting force N
F
add
Additional force (e. g. backing force) N
g Gravitational acceleration (g = 9.81 m/s
2
)m/s
2
J Moment of inertia of driving roller kgm
2
J
sum
Total moment of inertia kgm
2
lConveying length m
m
L
Mass of the payload kg
m’
L
Mass of the line load kg/m
m
Chn
Mass of the transport chain kg
m
add
Additional mass (e. g. by deflectors) kg
M
App
Required torque of the application (without losses) Nm
M
th,App
Required torque of the application (with losses) Nm
M
sds
Stationary torque Nm
s Path (translatory) m
v Speed (translatory) m/s
α Angular acceleration rad/s
2
β Angle of tilt °
η
Chn
Chain efficiency
ϕ Angle rad
μ
Gdn
Coefficient of friction of the chain to the supporting surface
μ
L
Coefficient of friction of the load to the chain
ω Angular velocity rad/s
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